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Row = [] for j in range(3): The invalid syntax says that it is some were in my printboard function. Unfortunately math is not my strong suit and i cannot seem to. You can make a tic tac toe game using the folowing code : Return random.randint(0, 1) def fix_spot(self, row, col, player): (this is for a college assignment) i have written the following function to do so: In this case, the printboard(theboard) line tells the script to print the theboard dictionary.

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Right now, the code returns the string loss when the player loses. Self.board = [] def create_board(self): So i looked online and saw other ways to create a tic toe table but i couldn't quite understand it. I need help figuring out how to calculate the record for wins, losses, and ties.

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The invalid syntax says that it is some were in my printboard function. In this case, the printboard(theboard) line tells the script to print the theboard dictionary. I need help figuring out how to calculate the record for wins, losses, and ties. You can make a tic tac toe game.

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(this is for a college assignment) i have written the following function to do so: Return random.randint(0, 1) def fix_spot(self, row, col, player): When i try to run it nothing happens and it says there is invalid syntax. The board in def printboard(board) tells the function to accept an argument.

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So i looked online and saw other ways to create a tic toe table but i couldn't quite understand it. You can make a tic tac toe game using the folowing code : The board in def printboard(board) tells the function to accept an argument or parameter when the function.

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I want it to return 1, for one loss. Return random.randint(0, 1) def fix_spot(self, row, col, player): This means you could theoretically have different boards printed by passing different dictionaries to the function. So i looked online and saw other ways to create a tic toe table but i couldn't.

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You can make a tic tac toe game using the folowing code : The board in def printboard(board) tells the function to accept an argument or parameter when the function is called. This means you could theoretically have different boards printed by passing different dictionaries to the function. I just.

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This means you could theoretically have different boards printed by passing different dictionaries to the function. Return random.randint(0, 1) def fix_spot(self, row, col, player): The board in def printboard(board) tells the function to accept an argument or parameter when the function is called. Unfortunately math is not my strong suit.

Right Now, The Code Returns The String Loss When The Player Loses.

In this case, the printboard(theboard) line tells the script to print the theboard dictionary. I just want ideas to tidy it up and make the code look better many thanks def display_board(bo. So i looked online and saw other ways to create a tic toe table but i couldn't quite understand it. The board in def printboard(board) tells the function to accept an argument or parameter when the function is called.

Return Random.randint(0, 1) Def Fix_Spot(Self, Row, Col, Player):

This code only checks for horizo. I need help figuring out how to calculate the record for wins, losses, and ties. I attempted to use an array to create my tic tac toe board but i can't seem to print it. Unfortunately math is not my strong suit and i cannot seem to.

(This Is For A College Assignment) I Have Written The Following Function To Do So:

The invalid syntax says that it is some were in my printboard function. Row = [] for j in range(3): This means you could theoretically have different boards printed by passing different dictionaries to the function. Self.board = [] def create_board(self):

When I Try To Run It Nothing Happens And It Says There Is Invalid Syntax.

I want it to return 1, for one loss. You can make a tic tac toe game using the folowing code :